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Novosadov [1.4K]
3 years ago
13

The proctoct of 5 and a odd number will end in

Mathematics
1 answer:
NARA [144]3 years ago
8 0

The product of 5 and an odd number gives an odd number since;

5 is a product number and;

Product of odd numbers is an odd number.

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SUM OF ANGLES IN A TRIANGLE THEOREM (SATT)
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3 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
Paola is planning her summer vacation. She wants to buy maps and atlases to use in her planning. The maps cost $3.00 and the atl
VladimirAG [237]
She can buy 4 atlases and 5 maps


3 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
It takes Mario and Jessica 15 minutes to set up 5 tables. If Mario and Jessica work at a constant rate, which best describes a p
AfilCa [17]

Answer:

3 minutes per table

Step-by-step explanation:

15 minutes = 5 tables

to get how much it will be per table, divided both sides by 5

since 5 / x = 1 and x would be 5

15 / 5 minutes = 5 / 5 tables

3 minutes = 1 table

5 0
1 year ago
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