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mixer [17]
3 years ago
10

In a bag of candy, Marsha found that there were 7 red, 8 blue, 5 yellow, and 9 greens pieces of candy. Marsha put all of the pie

ces of candy back in the bag, and drew one piece of candy out.
Part A:
Complete the following chart to determine the probability that Marsha drew each of the following pieces of candy.

Part B:
Marsha now wishes to determine compound probability. Complete the following chart to determine the probability that Marsha drew each of the following pieces of candy.

If you cannot see, zoom in. Don’t answer if you don’t know the answer. Whoever answers correctly will get Brainliest!

SAT
1 answer:
Lunna [17]3 years ago
8 0

Answer:

PART A

  • Red: 7/29
  • Blue: 8/29
  • Yellow: 5/29
  • Green: 9/29

PART B

  • Red or blue: 7/29 + 8/29 = 15/29
  • Yellow or green: 5/29 + 9/29 = 14/29
  • Blue or yellow or green: 8/29 + 5/29 + 9/29 = 22/29

Explanation:

In this case where the question is asking or <u>OR</u> and the events are <u>mutually exclusive</u> (Mutually exclusive meaning you can't attain two or three different colors in one pick), the compound probability is the sum of the probability of each component event (Probability of Red <u>OR</u> Blue = P(Red) + P(Blue) = 7/29 + 8/29 = 15/29)

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