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gtnhenbr [62]
3 years ago
12

Together, teammates Pedro and Ricky got 2680 base hits last season. Pedro had 284 more hits than Ricky. How many hits did each p

layer​ have?
Mathematics
1 answer:
katrin [286]3 years ago
5 0

Answer: einstein

Step-by-step explanation:

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Guys please help me please
Elza [17]

y + 2007 = 5/29x

5/29 is the slope and 2007 is the y-intercept

4 0
3 years ago
Express 500 g as a percentage of 2.5 kg.​
azamat

Answer:

500 grams is 20 percent of 2.5 kg

Step-by-step explanation:

500*100 = 50,000

50,000/2500=20

8 0
3 years ago
Read 2 more answers
If the triangles angles has the degrees of 100°and 43° what would be the next angle?
ohaa [14]

Answer:

Step-by-step explanation:

Since all the angles of triangle add up to 180 degrees,

Missing angle +100 +43=180.

Let the missing angle be 'x'.

Then, x + 100 +43 =180

or, x + 143 = 180

or, x = 180 - 143 = 37 degrees

So, the next angle is 37 degrees

5 0
3 years ago
10+4(-8q-4)<br>simplify to create an equivalent expression​
Alekssandra [29.7K]
10+4(-8q-4)
14(-8q-4)
then distribute 14 to -8q-4
3 0
3 years ago
Read 2 more answers
What is the simplified form of the expression? 6/√5−√2
tester [92]

Answer:

The expression can be simplified into 2\,\sqrt{5} +2\sqrt{2}

with no square roots in the denominator

Step-by-step explanation:

We are considering the expression  \frac{6}{\sqrt{5}-\sqrt{2}  }  which I believe is what you wanted to type in your question.

The idea behind simplification of the expression, is normally associated with the rationalization of the denominator by eliminating irrational numbers from it. This means to get rid of any "irrational" number expression (like in this example, the square root of non-perfect square numbers (\sqrt{5}\,\,\,and \,\,\sqrt{2}).

We proceed by writing this quotient in an equivalent form by multiplying its numerator and its denominator by what is called the "conjugate" of the denominator. In our case, multiply by " (\sqrt{5} +\sqrt{2}) ", because such product will allow the denominator to become a rational number:

\frac{6}{\sqrt{5}-\sqrt{2}  }\,*\,\frac{(\sqrt{5}+\sqrt{2} )}{(\sqrt{5}+\sqrt{2}) } =\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{\sqrt{5}^2-\sqrt{2}^2 }=\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{3}=2\,\sqrt{5} +2\sqrt{2}

where we find all square roots eliminated from the denominator

5 0
3 years ago
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