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2 years ago

Answer quick Calculate the slope of the line going through A(-4,3) and B(0,6)

Mathematics

1 answer:

NeX [460]2 years ago

3 0

Answer:

Step-by-step explanation:

$\boxed{slope = \frac{y1 - y2}{x1 - x2} }$

☆ (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate

Slope of line

$= \frac{6 - 3}{0 - ( - 4)}$

$=\frac{3}{4}$

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Urgent help pleaseeeeeee

Helga [31]

Answer:

2x - 10 = 10 - 3x

Simplifying

2x + -10 = 10 + -3x

Reorder the terms:

-10 + 2x = 10 + -3x

Solving

-10 + 2x = 10 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.

-10 + 2x + 3x = 10 + -3x + 3x

Combine like terms: 2x + 3x = 5x

-10 + 5x = 10 + -3x + 3x

Combine like terms: -3x + 3x = 0

-10 + 5x = 10 + 0

-10 + 5x = 10

Add '10' to each side of the equation.

-10 + 10 + 5x = 10 + 10

Combine like terms: -10 + 10 = 0

0 + 5x = 10 + 10

5x = 10 + 10

Combine like terms: 10 + 10 = 20

5x = 20

Divide each side by '5'.

x = 4

Simplifying

x = 4

3 0

2 years ago

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Find the common ratio of the sequence. –172, –86, –43, –21.5, . . .

seropon [69]

If you divide each number by the previous one, you get:

-86 / -172 = 1/2
-43 / -86 = 1/2
-21.5 / -43 = 1/2

The common ratio is 1/2 = 0.5

4 0

3 years ago

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Is that right? <br><br> If not please help me out.

Alex73 [517]

Answer:

Yeah.it is right

Step-by-step explanation:

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3 years ago

Solve. Show all of your steps. 3.) 3(5 + 2) - 2 cubed

Aleonysh [2.5K]

Answer:

4 3=64

Step-by-step explanation:

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2 years ago

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The equation of line r is y = -1\2x - 4. If line s runs perpendicular to line r and passes through (4, -3), what would be the eq

Scrat [10]

First off, what's the slope of "r" anyway, $\bf y=\stackrel{slope}{-\cfrac{1}{2}}x-4$ .

low and behold, since "r" is in slope-intercept form, notice, it has a slope of -1/2.

now, any line perpendicular to "r", will have a negative reciprocal slope to it, that is,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{2}\\\\
negative\implies +\cfrac{1}{{{ 2}}}\qquad reciprocal\implies + \cfrac{{{ 2}}}{1}\implies 2$

so we're really looking for a line whose slope is 2, and runs through 4,-3,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
% (a,b)
&&(~{{ 4}} &,&{{ -3}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 2
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-3)=2(x-4)\implies y+3=2x-8
\\\\\\
y=2x-11$

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3 years ago