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3 years ago

Cv0627 answer this :))

Mathematics

1 answer:

12345 [234]3 years ago

5 0

they took my first answer off, so i came back. but honestly thank you for the points. have an amazing day!

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Find the 79th term of the following arithmetic sequence. 5,11, 17, 23...

NikAS [45]

Answer:

the answer is 479.

Step-by-step explanation:

to make it simpler, pretend you start from 1. 1,7,so on. multiply six by 79, to get 474. but because you are starting from 5 and not 1, you have to add 5 on.

sorry im super bad at math so this might be wrong

4 0

3 years ago

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For somebody that need it

djverab [1.8K]

Answer:

is there a question in this? lol, if not, tyy!!

Step-by-step explanation:

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3 years ago

James buys 2 4/5 kilograms of red potatoes. He buys yellow potatoes that weigh 3/4 as much as the red potatoes.

Illusion [34]

Answer:

Step-by-step explanation:

2 4/5 kg” would equal as a whole number 14/5 kgs, or 2.8, divided by 3/4’s would be 2.1 kgs.

As a mixed number there would be 2 1/10’s.

2 1/10.

8 0

3 years ago

Jamie evaluated this expression. StartFraction left-bracket (2 cubed) (2) right-bracket Superscript 4 Baseline Over 2 Superscrip

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Given the expression

$\frac{(2^3)(2)^4}{2^{10}} \\$

Using the following laws of indices;

$\frac{a^m}{a^n} = a^{m-n}\\a^m \times a^n = a^{m+n}$

The expression becomes;

Step 1: Multiplication rule

$=\frac{(2^3)(2)^4}{2^{10}} \\= \frac{2^{3+4}}{2^{10}}\\= \frac{2^7}{2^{10}}$

Using the division rule of exponent (Quotient of powers);

$= \frac{2^7}{2^{10}} \\= 2^{7-10}\\= 2^{-3}\\also \ a^{-m} = \frac{1}{a^m}\\ 2^{-3}= \frac{1}{2^3}\\\frac{1}{2^3} = \frac{1}{8}$

Hence the result of the expression is 1/8

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3 years ago

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