Answer:
Figure (i) and (iv)
Step-by-step explanation:
Given:
Optional figure is given in attached file.
We need to find two figures that are similar to the 5 by 10 figure.
All the given figure are
form.
Where m represent the number of rows and n represent the number of columns.
Solution:
Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.
So we need to find two such figures whose number of columns is double of the number of rows.
From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.
Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.
Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).
Answer:
0.75
Step-by-step explanation:
Since we use the base 10 decimal system, first convert 3/4 to out of 100:
3/4 = 75/100
We divide 75 by 100 to get 0.75
Answer: Please include more information
Step-by-step explanation:
Answer:
Any number less than greater than or equal to 18
Step-by-step explanation:
Let
rA--------> radius of the circle R
rB-------> radius of the circle S
SA------> the area of the sector for circle R
SB------> the area of the sector for circle S
we have that
rA=3 ft
rB=6 ft
rA/rB=3/6----> 1/2----------->
rB/rA=2
SA=2π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(2) ^2*(2π)--->
SB----------- > 8π ft²
the answer is
the area of the sector for circle S is 8π ft²