3 years ago

PLEASE ANSWER ASAP! 20 POINTS!

1 answer:

6 0

73883hebdh heyrbhehebebe

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Hunter-Best [27]

They site there sources or give information to prove why there point is correct

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3 years ago

N76 [4]

26/100 or simplified to 13/50

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3 years ago

Rufina [12.5K]

Answer: $\frac{^{10}C_5}{^{12}C_5}$

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is $^{10}C_5$

no of ways in which any 5 engines are selected from a total of 12 engines is

$^{12}C_5$

Therefore the required probability = $\frac{^{10}C_5}{^{12}C_5}$

= $\frac{7}{22}$ =0.318

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3 years ago

Katarina [22]

A) <
You are welcome and if someone else answers, mark me brainliest

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3 years ago

UNO [17]

Answer:

PUSHIN

Step-by-step explanation:

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3 years ago