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svetoff [14.1K]
2 years ago
5

Kaelyn has 14 coins that have a value if $1.20. she only had dimes and nickles. How many nickels does kaelyn have?​

Mathematics
2 answers:
Leni [432]2 years ago
6 0

Answer:

24

Step-by-step explanation:

evablogger [386]2 years ago
4 0

Answer:

10 dimes and 4 nickels

Step-by-step explanation:

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-4x + 2x + 3x + 8<br> Asap
Talja [164]

Answer:

x + 8

Step-by-step explanation:

1. To simplify this expression, we have to combine like terms.

  • (-4x + 2x + 3x) + (8)
  • (-2x + 3x) + (8)
  • x + 8

Therefore, the answer is x + 8.

4 0
2 years ago
2 rational numbers who’s difference is rational
horrorfan [7]

Answer: (5+√2) and (3+√2)

Step-by-step explanation: Let (5+√2) and (3+√2) be  two irrational numbers

                                             Difference = (5+√2) - (3+√2)

                                             Difference = 2

                                             2 is a rational number

6 0
2 years ago
Marco has a jug with 37 1/2 ounces of juice. He wants to use some small cups to pass out samples of the juice Each cup holds 2 1
vladimir2022 [97]
37.5 divided by 2.5 is equal to 15.
4 0
3 years ago
Read 2 more answers
Mentally confused, please help.
garik1379 [7]
If you are looking for the surface area of the cube, it is 169. The equation for the surface area of a square is base times height. This would mean it’s 13x13 since all the sides are the same. 13x13=169
5 0
2 years ago
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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
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