Answer:
0.86
Step-by-step explanation:
The z-score we need to make the comparison is given by
where
= the standard deviation established in the study
n = the sample size
and for the Normal distribution N(0,1) we want to find
<em>P(X > -1.0801) </em>
By using a spreadsheet or the table attached, we find that
P(X > -1.0801) = 0.86
(See picture attached)
