All categories

2 years ago

Find the first three common multiplies 6 and 8

Mathematics

1 answer:

Alexus [3.1K]2 years ago

7 0

Answer:

24,48,72

Step-by-step explanation:

multiples of 6- 6,12,18,24,30,36,42,48,54,60,66,72

multiples of 8- 8,16,24,32,40,48,56,64,74,80

You might be interested in

Given m||n, find the value of x. + (5x+2) (4x+6)°

Anon25 [30]

The required value of x is 4.

7 0

2 years ago

How does the method for solving equations with fractional or decimal coefficients and constants compare with the method for solv

I am Lyosha [343]

Answer:

Step-by-step explanation:

When solving equations with fractional or decimal coefficients, the equations needs to be multiplied by the multiple of denominator such that the equations have integer coefficients and constants

6 0

2 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

2 years ago

1. How many degrees is x .x 41 82 20.5 o 41 О 10

Alja [10]

Answer:

Option (1)

Step-by-step explanation:

By the inscribed angle theorem inside a circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

$\frac{1}{2}$ [m(arc AB)] = m(∠ABC)

m(arc AB) = 2[m(∠ABC)]

x = 2(41°)

x = 82°

Option (1) is the correct option.

5 0

2 years ago

Help pleaseeee!!!! Geometry

puteri [66]

Tan x=opposite/adjacent
cot x=adjacent/opposite

so you need to inverse the fraction
tan x=.78 as a fraction is 78/100
-> inversed= 100/78=1.28=cot x

so it is the second option

8 0

2 years ago

Find the first three common multiplies 6 and 8​

Find the first three common multiplies 6 and 8