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alukav5142 [94]
2 years ago
13

Find the first three common multiplies 6 and 8​

Mathematics
1 answer:
Alexus [3.1K]2 years ago
7 0

Answer:

24,48,72

Step-by-step explanation:

multiples of 6- 6,12,18,24,30,36,42,48,54,60,66,72

multiples of 8- 8,16,24,32,40,48,56,64,74,80

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Joe flipped a coin 100 times. It landed heads
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Answer:

48%

Step-by-step explanation:

48 out of 100 = 48%

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6 0
3 years ago
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What is the answer to this equation:<br><br> 1/2 + 8/3
topjm [15]

Answer:

9-5 or 1/4-5

Step-by-step explanation:


6 0
3 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

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8 0
2 years ago
In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q
siniylev [52]

Answer:

∠Q  = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

Hence using the notation

SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering  ∠Q and the given sides

PR=16cm is the opposite side,

PQ= 12 cm is the adjacent side hence we use TOA

Tan Q = 16/12 =

Q = Arc tan 16/12

= 53.13 degrees

5 0
2 years ago
Loan
diamong [38]
B

Explanation: I guessed and it was right
5 0
2 years ago
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