I think it is skin cells and blood cells because sperm and egg cells are haploid, so they only have one copy. I’m honestly not 100% sure tho
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Options for the question have not been given. They are as follows:
A. dinoflagellates.
B. Choanoflagellida.
C. Stramenopiles.
D. euglenoids.
E. foraminifera.
Answer:
C. Stramenopiles
Explanation:
Stramenopiles or heterokonts are a part of Chromista kingdom. They comprise of both unicellular and multicellular protists. They are characterized by presence of two dissimilar flagella in the motile life cycle stage. Their chloroplast is also surrounded by four membranes which indicates origin from symbiotic relationship. They include many classes like diatoms, golden algae and brown algae. Brown algae belongs to the class Phaeophyceae. They are marine multicellular algae and are commonly known as seaweeds.
Interphase is the longest part of the cell cycle. This is when the cell grows and copies its DNA before moving into mitosis.
