Ask question

Ask question

All categories

3 years ago

8

How many different triangles can be made with the angles 45 degree, 45 degree, 90degree ?

2 answers:

pychu [463]3 years ago

7 0

Answer:

C: one triangle

Step-by-step explanation:

well a triangle = 180°

45+45=90

90+90=180

Oksi-84 [34.3K]3 years ago

6 0

I think C I hope this helps

You might be interested in

How long can a cat live ?

PSYCHO15rus [73]

Step-by-step explanation:

I think 10-15years

not sure tho

4 0

3 years ago

Read 2 more answers

Given f(x)=21x+14, find f(5)

loris [4]

$f(5)=21\cdot5+14=105+14=119$

6 0

3 years ago

The table represents a linear function.<br> What is the slope of the function?

TEA [102]

Answer:

-4

Step-by-step explanation:

The function is linear; therefore, the slope of the line joining any two points is the same.

We take any two points from the table and compute the slope or rise/ run between them— let is take points (-4, -2) and (-2, -10).

The slope $m$ of the line joining the points is

$m=\dfrac{\Delta y }{\Delta x } =\dfrac{-2-(-10)}{-4-(-2)} \\\\\boxed{m=-4}$

The slope of the function is -4.

3 0

3 years ago

Anybody can give me the answer? Please

Shtirlitz [24]

b. One hundred and fifty (150) square feet

8 0

4 years ago

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

4 0

3 years ago