$s^2-4=s^2-2^2=(s-2)(s+2)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)\\\\s^2-5s+6=s^2-2s-3s+6=s(s-2)-3(s-2)=(s-2)(s-3)\\\\\text{Therefore}\ LCD(s^2-4,\ s^2-5s+6)=(s-2)(s+2)(s-3)$

4 0

3 years ago

What is the area of a parallelogram with a base of 38 meters and a height of 12 meters?

8090 [49]

For this case we have by definition that the area of a parallelogram is given by:

$A = b * h$

Where:

b: It's the base

h: It's the height

According to the data we have:

$b = 38\ m\\h = 12 \ m$

Substituting in the formula:

$A = 38 * 12\\A = 456$

The area of the parallelogram is $A = 456 \ m ^ 2$

Answer:

$A = 456 \ m ^ 2$

4 0

3 years ago

Read 2 more answers

Method of Transportation Percent of Students

eduard

No. Because she only asked the people who was walking to school

5 0

3 years ago