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irga5000 [103]
3 years ago
8

8.) What is the probability of rolling a 2 on a six-sided number cube and flipping heads on a coin? *

Mathematics
1 answer:
Leto [7]3 years ago
4 0
The probability of rolling a 3 on a six sided number cube is 1/6
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maria [59]

Answer:

option 2 is correct

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If a = b and b = c, which statement must be true?
torisob [31]

Answer:

a=c

Step-by-step explanation:

This is because of the transitive property; which states that if a=b and b=c, then a=c.

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I need the answer asap
eimsori [14]

Answer:

22873

Step-by-step explanation:

you have to put the value from 6-94 in n the given equation 5n+7.

for e.g= (5×6+7)+(5×7+7)+(5×8+7)+ _____ so on

3 0
3 years ago
100 POINTS!! PLEASE HELP IM REALLY CONFUSED
11111nata11111 [884]

Answer:

1:

<A=½(arcJL)=½(70+120)=35+60=95°

[inscribed angle is half of central angle]

2:

<W=½arcVX=½(130)=65°

[inscribed angle is half of central angle]

3.

<E=½(arcDC)=½(90)=45°

[inscribed angle is half of central angle]

4.

<R=½(arcXZ)=½(110+62)=86°

[inscribed angle is half of central angle]

5.

<B=½(arc DC)=½×104°=52°

[inscribed angle is half of central angle]

6.

<K=90°

[inscribed angle in a diameter is complementary]

<K+<J+<L=180°(sum of interior angle of a triangle]

<L=180°-90°-53°=37°

again

arc JK=2×<L=2×37=74°

3 0
3 years ago
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
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