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leva [86]
2 years ago
10

The length of the garden is 10 feet more than twice its width. The perimeter of the garden is 170 feet.

Mathematics
1 answer:
icang [17]2 years ago
3 0

Answer:

The width of the garden is 25 feet

The length of the garden is 60 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle

= P = 2L + 2W

Where L = Length, W = Width

The length of the garden is 10 feet more than twice its width.

P = 170

L = 2W + 10

Hence,

170 = 2(2W + 10) + 2W

170 = 4W + 20 + 2W

Collect like terms

170 - 20 = 6W

150 = 6W

W = 150/6

W = 25 feet

The width of the garden is 25 feet

Remember

L = 2W + 10

L = 2(25) + 10

L = 50 + 10

L = 60 feet

The length of the garden is 60 feet

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Can someone solve this
marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325  See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets   1 - ((6*12+6)/80)²  ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375


Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325


In summary we can state that:

A = 0.049375

B =  -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
#SPJ1

4 0
1 year ago
If f(x) = 2x^4, then f'(3) =
valkas [14]

To find f'(3) (f prime of 3), you must find f' first.  f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is \frac{d}{dx} [x^{n} ] =nx^{n-1}.  In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = \frac{d}{dx}(2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

f'(3) = 216

<h3>Answer:</h3>

f'(3) = 216

6 0
2 years ago
6. Let f and g be differentiable functions
Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate h(x)=f(x)g(x) we will need the product rule:

h'(x)=f'(x)g(x)+f(x)g'(x).

We have h'(x)=f(x)g'(x), so the following equation is true by the transitive property:

f'(x)g(x)+f(x)g'(x)=f(x)g'(x)

By subtraction property we have:

f'(x)g(x)=0

Since g(x) \neq 0, then we can divide both sides by g(x):

f'(x)=\frac{0}{g(x)}

f'(x)=0

This implies f(x) is constant.

So we have that f(x)=c where c is a real number.

Since f(0)=1 and f(0)=c, then by transitive property 1=c.

So f(x)=1.

Checking:

h(x)=1 \cdot g(x)

h'(x)=g'(x)=1 \cdot g'(x)

So the following conditions were met.

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(b) The train is 61 cm long and travels at a speed of 18 cm/s.
xz_007 [3.2K]

Answer:

It goes 18 cm every second:

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The bridge is 72 cm long.

Hope this helps!

3 0
3 years ago
Read 2 more answers
If arc VY = 132° and ∠YUV = 41°, what is the measure of arc XV?
Tom [10]

Answer:

50

Step-by-step explanation:

Use this equation

\frac{b - a}{2}  = angle \: yuv

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Substitute the equation in

\frac{132 - a}{2}  = 41

132 - a = 82

- a =  - 50

a = 50

so our arc measure is 50

5 0
2 years ago
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