Factor the expression below. A. (x − 6)(x − 6) B. 6(x2 − x + 6) C. (x − 6)(x + 6) D. (x + 6)(x + 6)

Thirty children from an after-school club went to the matinee. This is 20% of the children in the club. How many children are in

Setler [38]

Answer:

Step-by-step explanation:

20%=30

x by 5 to get 100%

100%=150

8 0

2 years ago

Read 2 more answers

An animal shelter takes in an average of 5 animals per day. The shelter must keep its total occupancy below 300. Currently, the

Serggg [28]

Answer:

B. x<27

Step-by-step explanation:

The shelter has 165 animals.

The shelter must keep its total occupancy below 300.

The shelter takes in an average of 5 animals per day. If x is the number of days, then in x days the shelter takes 5x animals. In total there will be

165+5x animals. This number must be less than 300, so

$165+5x< 300\\ \\5x< 300-165\\ \\5x< 135\\ \\x< 27$

8 0

2 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago

I need help on this quick

Pachacha [2.7K]

Answer:

The hypotenuse to the nearest tenth is 8.1

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

Let a be the x leg and b be the y leg

a = 7 units

b= 4 units

7^2 + 4^2 = c^2

49+ 16 = c^2

65 = c^2

Take the square root of each side

sqrt(65) = sqrt(c^2)

8.062257748 =c

To the nearest tenth

8.1 =c

7 0

2 years ago

if a town with a population of 500 doubles in size ever 9 years, what will the population be 36 years from now?

s344n2d4d5 [400]

The population of the town in 36 years would be 8000.

<h3>What would be the population of the town in 36 years?</h3>

The formula that can be used to determine the town's population is:
FV = P (1 + r)^n

Where:

FV = Future value
P = Present value
R = rate of growth = 100%
N = number of years = 36/9 = 4

500 x 2^4 = 8000

To learn more about future value, please check: brainly.com/question/18760477

4 0

2 years ago