Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.
<h3>When does a histogram represent a normal distribution?</h3>
A histogram represents a normal distribution if it symmetric.
In this problem, we have that:
- 57% of the grades are on the left tail.
- 25% of the grades are on the center.
- 18% are on the right tail.
Since the percentages at the tails are different, the histogram is not symmetric, and the grades shown in the math class below are not normally distributed.
More can be learned about the normal distribution at brainly.com/question/24537145
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Answer:
the solution is the last one.
Step-by-step explanation:
We know that for a second grade equation of the type:
ax^2 + bx + c = 0
The solution will be given by the quadratic formula, which states that:
x1 = [-b + sqrt(b^2 - 4ac)]/2a
x2 = [-b - sqrt(b^2 - 4ac)]/2a
So, according to the solution, we have:
x1 = [-5 + 2sqrt(7)]/3
Then:
2a = 3
-b = 5
b^2 - 4ac = 28
Solving each equation:
a = 2/3
b= -5
c = 9/8
None of the alternatives equals the values obtained before. So we can say that the expression is simplified.
Now we knoe what the first and second equation are wrong because b is not equal to -5.
So we have the other two alternatives, where b=-10. This gives us an idea that maybe, the equation is simplified by two. If that's the case:
then:
2a = 6
b= -10
b^2 - 4ac = 112
Then b=-10, a = 3 and c=-1
So the solution is the last one.
Answer:
(6.2, 4.5)
Step-by-step explanation:
That point (P) will be the weighted average of the end points, where each weight is the proportion of the segment at the end farthest from the point:
P = (3A +1B)/(3+1)
= (3·7.5 +2.3, 3·4.2 +5.4)/4
= (24.8, 18)/4
= (6.2, 4.5)
Answer:
x=3
Step-by-step explanation:
No matter what happens to the y value, x always stays on the number 3, so y does not matter for this equation, it is simply x=3.