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statuscvo [17]
3 years ago
6

What is the equivalent recursive definition for an = 12+ (n - 1)3?

Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

A_1 = 12

A_n = A_{n-1} + 3

Step-by-step explanation:

Given

A_n =12+(n-1)3

Required

Write as recursive

We have:

A_n =12+(n-1)3

Open bracket

A_n =12+3n-3

A_n =12-3+3n

A_n =9+3n

Calculate few terms

A_1 =9+3*1 = 9 + 3 = 12

A_2 =9+3*2 = 9 + 6 = 15

A_3 =9+3*3 = 9 + 9 = 18

The above shows that the rule is to add 3.

So, we have:

A_1 = 12

A_n = A_{n-1} + 3

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Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

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And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

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Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

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Therefore, <em>the probability of Event B</em> is:

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