Using the Empirical Rule, it is found that the correct statements are given by:
- About 16% of all exam scores are less than 86.5 points.
- About 16% of all exam scores are greater than 89.5 points.
- About 84% of all exam scores are less than 89.5 points.
<h3>What does the Empirical Rule state?</h3>
It states that, for a normally distributed random variable:
- Approximately 68% of the measures are within 1 standard deviation of the mean.
- Approximately 95% of the measures are within 2 standard deviations of the mean.
- Approximately 99.7% of the measures are within 3 standard deviations of the mean.
We also have to consider that the normal distribution is symmetric. Then, alog with the mean of 88 and standard deviation of 1.5, the correct statements are given by:
- About 16% of all exam scores are less than 86.5 points(more than 1 standard deviation below the mean, the percentage, considering the symmetry, is 0.5 x 32 = 16%).
- About 16% of all exam scores are greater than 89.5 points, due to the same explanation as above.
- About 84% of all exam scores are less than 89.5 points, as the percentage is 50%(all below the mean) + 50% x 68%(one standard deviation above the mean) = 84%.
More can be learned about the Empirical Rule at brainly.com/question/24537145
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Answer:b is a abreveation
Step-by-step explanation:
You take b and multiply it with 3 then subtract 4 divide that answer by 2 then that =c
Answer:
The reasonable domain to plot the growth function is the interval [0,9]
![0\ days\leq d\leq 9\ days](https://tex.z-dn.net/?f=0%5C%20days%5Cleq%20d%5Cleq%209%5C%20days)
Step-by-step explanation:
In this problem we have a exponential function of the form
![f(d)=a(b^d)](https://tex.z-dn.net/?f=f%28d%29%3Da%28b%5Ed%29)
where
f(d) is the radius of the algae in mm
d is the number of days
a is the initial value or y-intercept
b is the base
r is the rate of growth
b=1+r
we have
![a=9\ mm\\b=1.04\\r=1.04-1=0.04=4\%](https://tex.z-dn.net/?f=a%3D9%5C%20mm%5C%5Cb%3D1.04%5C%5Cr%3D1.04-1%3D0.04%3D4%5C%25)
we have
![f(d)=9(1.04^d)](https://tex.z-dn.net/?f=f%28d%29%3D9%281.04%5Ed%29)
For f(d)=12.81 mm
substitute in the function and solve for d
![12.81=9(1.04^d)](https://tex.z-dn.net/?f=12.81%3D9%281.04%5Ed%29)
![(12.81/9)=(1.04^d)](https://tex.z-dn.net/?f=%2812.81%2F9%29%3D%281.04%5Ed%29)
Apply log both sides
![log(12.81/9)=log(1.04^d)](https://tex.z-dn.net/?f=log%2812.81%2F9%29%3Dlog%281.04%5Ed%29)
![log(12.81/9)=(d)log(1.04)](https://tex.z-dn.net/?f=log%2812.81%2F9%29%3D%28d%29log%281.04%29)
![d=log(12.81/9)/log(1.04)](https://tex.z-dn.net/?f=d%3Dlog%2812.81%2F9%29%2Flog%281.04%29)
![d=9\ days](https://tex.z-dn.net/?f=d%3D9%5C%20days)
therefore
The reasonable domain to plot the growth function is the interval [0,9]
![0\ days\leq d\leq 9\ days](https://tex.z-dn.net/?f=0%5C%20days%5Cleq%20d%5Cleq%209%5C%20days)
Answer:
All the lines have the same slope, m = 0, showing that they are all parallel.
Step-by-step explanation:
PLATO
Answer:
![\frac{24}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B5%7D)
Step-by-step explanation: