Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
#SPJ1
Answer:
c 1464 cm ^2 is the answer
Answer:
Step-by-step explanation: the first time you get 0.75 and the second time you get 0.125 hope this helped
First you need to subtract 750-600= 150.
Then 150 time .35=52.5.
Lastly 52.5+49.99= 102.49
This is a trapezoid and the trapezoid formula is b1 plus b2/ 2 times height.
17 plus 5 is 22. Divided by 2 is 11.
Now, we have to multiply 11 by the height : 5.
11 times 5 is 55 and that is your area. 55 units squared.
