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Oksanka [162]
3 years ago
10

The length, in millimeters of each side of a square shaped electronic chip is a rational number. What statement is true about th

e length of the diagonal of the chip
Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

The diagonal is irrational because it is a product of a rational and an irrational number

Step-by-step explanation:

The options are not given. However, the question is still answerable.

Given

Shape: Square

Length: Rational

Since the side length is said to be rational, I'll answer the question based on whether the diagonal is rational or not.

Having said that:

The diagonal (d) of a square with side length (l) is calculated using Pythagoras theorem.

d^2 = l^2 + l^2

d^2 = 2l^2

Take positive square root of both sides

d = \sqrt{2l^2}

Split:

d = \sqrt{2} * \sqrt{l^2}

d = \sqrt{2} *l

Recall that the side length (l) is rational.

However, \sqrt 2 is irrational.

So, the product of l and \sqrt 2 will be irrational

Hence:

The diagonal is irrational

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We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.

This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>

Explanation:

In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.

So we want to find a and b such that 5, a, b, 135 is a geometric sequence.

If the common ratio is r then:

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Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>

Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>


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