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3 years ago

I'm a little confused on how to answer #2

Mathematics

1 answer:

scoundrel [369]3 years ago

3 0

Ten is to the 6th power so there are 6 zeroes.

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What is 28- 12.5% decrease???

OLEGan [10]

Ok so I assume
28 and decreased by 12.5%

percent means partst out of 100 so
12.5%=12.5/100=0.125
first find 12.5% of 28 then subtract
0.125 times 28=3.5
decrease
28-3.5=24.5

answer is 24.5

3 0

3 years ago

I do not know what to put and this was due yesterday

atroni [7]

Answer:

Your answer will be x=2

Step-by-step explanation:

Five plus 6 times a number is equal to 21 minus 2 times the number

Your equation is this:

5+6x=21-2x

Subtract 6x from both sides

5+6x-6x=21-2x-6x

5=21-8x

subtract 21 on both sides

5-21=21-21-8x

-16=-8x Divide -8 on both sides

2=x

Hope this helps :)

8 0

2 years ago

Write the slope-intercept of the equation of the line through the given point of (5, 0) with the slope 0.

Digiron [165]

Answer:

x = 5

Step-by-step explanation:

5 0

2 years ago

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gogolik [260]

35
“Negative times a negative is a positive”

3 0

2 years ago

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

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