Answer: 1
Step-by-step explanation:
Only one element is in the event space for rolling the sum of 12 with two dice
(6,6)
If you must roll the sum of 12 with two dice, you must have rolled 6 in the two dice
Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3)))) .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3))) ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3)) .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)
=2/sqrt(3) .... now rationalize
=2sqrt(3)/3
200 grams is is 0.2 kilograms, so you would pay $0.88 because 4.40x0.2=0.88
Your answer would be <span>6678.02</span>
Answer:
x=137
y=525-137
y=388
Step-by-step explanation:
Let the student tickets be x
Let the geral Admission tickets be y
x+y=525
y=525-x
4x+6y=2876 (subsitute for y)
4x+6(525-x)=2876
4x+3150-6x=2876
-2x=-274
x=137
y=525-137
y=388
Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.
Paul.
