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adoni [48]
3 years ago
15

Miss Mia needed to pack 7370 pencils for children's day. She packed some penils on Monday and 4228 pencils on Tuesday. She found

that she still needed to pack 340 pencils more. How many pencils did she pack on Monday?​
Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0
I think the answer is 2802 pencils
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Least common factor of 15 and 20
zavuch27 [327]

Answer: Lcm=60

Step-by-step explanation: but if you want lcf its always 1

6 0
3 years ago
Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri
Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after \frac{640}{7} miles

Step-by-step explanation:

Given

The table represents the car mileage

y = -\frac{1}{5}x + 31 --- The van

First, calculate the car's slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)

So, we have:

m = \frac{10.5 - 13.5}{180 - 60}

m = \frac{-3}{120}

m = -\frac{1}{40}

Calculate the equation using:

y = -\frac{1}{40}(x - 60)+13.5

y = -\frac{1}{40}x + 1.5+13.5

y = -\frac{1}{40}x + 15

m = -\frac{1}{40} implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

y = -\frac{1}{5}x + 31 --- The van

By comparison to: y = mx + b

m = -\frac{1}{5}

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

1/40 < 1/5

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

y = -\frac{1}{5}x + 31 --- The van

y = -\frac{1}{40}x + 15 --- The car

Equate both

-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15

Collect like terms

\frac{1}{40}x -\frac{1}{5}x  =-31 + 15

\frac{1}{40}x -\frac{1}{5}x  =-16

Take LCM

\frac{x - 8x}{40} = -16

\frac{- 7x}{40} = -16

Solve for -7x

-7x = -640

Solve for x

x = \frac{640}{7}

5 0
3 years ago
What is the slope of a line parallel to the line whose equation is y - x = 5 ? please explain answer
Trava [24]
The slope of a line is c. 1
6 0
3 years ago
Read 2 more answers
How do you do these questions?
Doss [256]

Step-by-step explanation:

(a) Fₙ₋₁ > 0, so Fₙ₊₁ > Fₙ.  Each term is bigger than the one before it, so the function is increasing, meaning the series will diverge to infinity.

(b) Fₙ₊₁ / Fₙ = (Fₙ + Fₙ₋₁) / Fₙ

Divide.

Fₙ₊₁ / Fₙ = 1 + (Fₙ₋₁ / Fₙ)

Rewrite the second fraction using negative exponent.

Fₙ₊₁ / Fₙ = 1 + (Fₙ / Fₙ₋₁)⁻¹

Take the limit of both sides as n approaches infinity.

lim(n→∞) Fₙ₊₁ / Fₙ = 1 + lim(n→∞) (Fₙ / Fₙ₋₁)⁻¹

Substitute with φ.

φ = 1 + φ⁻¹

Solve.

φ² = φ + 1

φ² − φ − 1 = 0

φ = [ -(-1) ± √((-1)² − 4(1)(-1)) ] / 2(1)

φ = (1 ± √5) / 2

Since the ratio can't be negative:

φ = (1 + √5) / 2

4 0
3 years ago
Which of the following could be the equation of the function below?
rodikova [14]

Answer:

y = 0.5 cosine (4 (x - pi/2)) - 2

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Taking the general form:

y = A cosine (Bx - Cπ)) + D

In the following case. the constants are:

y = 0.5 cosine (4x - 2π)) - 2

A: 0.5

B: 4

C: 2π

D: -2

The range of this function is:

range = [-|A|+D, |A|+D]

range = [-0.5-2, 0.5-2]

range = [-2.5, -1.5]

Which coincides with "It has a maximum at negative 1.5 and a minimum at negative 2.5"

At x = 0, the function value is:

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As indicated in "a curve crosses the y-axis at y = negative 1.5"

The period of the function is:

period: 2π/B

period = 2π/4 = π/2 or 2 cycles at π

as described in "It goes through 2 cycles at pi."

8 0
3 years ago
Read 2 more answers
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