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3 years ago

Given that (6,3) is on the graph of f(x), find the corresponding point for the function f(-1/2x)

Mathematics

2 answers:

Molodets [167]3 years ago

5 0

The correct answer is B or (3,6)

a_sh-v [17]3 years ago

3 0

Answer:

(-12, 3) is correct!

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Convert Standard form to Slope-intercept form:<br>3x - 2y = -16<br>

tiny-mole [99]

Answer

y= 3/2 + 8

Hope I helped you

4 0

3 years ago

Marley has read 112.5 pages of a book. By the end of today, she plans to have read at least a total of 360 pages. If she reads 4

e-lub [12.9K]

She will need 5 and a half hours. First step is to do 360-112.5 the pgs she read and her goal. then you'll get 247.5. To find how many hours you need to find the unit rate. so 247.5 divided by 45 is 5.5 hours.

hope this helped. can u mark me as the brainiest answer

6 0

4 years ago

Find the midpoint of AB if A is (-3,-3) and B is (6,6)?

blondinia [14]

(x, y)

When you are asked for the midpoint, just find the average for both the x and y components:

So the midpoint for A(-3, -3) and B(6, 6)

The xs components are -3, and 6, Average = (-3 + 6)/2 = 3/2 = 1.5

The ys components are -3, and 6, Average = (-3 + 6)/2 = 3/2 = 1.5

So the midpoint is (1.5, 1.5)

I hope this helps.

3 0

3 years ago

The following measurements (in picocuries per liter) were recorded by a set of argon gas detectors installed in a research facil

Reptile [31]

Answer:

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Step-by-step explanation:

Before building the confidence interval, we have to find the sample mean and the sample standard deviation.

Sample mean:

$\overline{x} = \frac{381.3+394.8+396.1+380}{4} = 388.05$

Sample standard deviation:

$s = \sqrt{\frac{(381.3-388.05)^2+(394.8-388.05)^2+(396.1-388.05)^2+(380-388.05)^2}{3}} = 8.58$

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 3.1824

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.1824\frac{8.58}{\sqrt{4}} = 13.65$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 388.05 - 13.65 = 374.4

The upper end of the interval is the sample mean added to M. So it is 388.05 + 13.65 = 401.7

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

4 0

3 years ago

Harry is paid £8.60 per hour for the first 30 hours he works each week. After 30 hours he is paid 1 and a half times the hourly

puteri [66]

Answer:

1404.81

Step-by-step explanation:

1277.1 +127.71 = i read it wrong the first time sorry

3 0

3 years ago