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erma4kov [3.2K]

2 years ago

13

What’s the difference between a supplementary and complementary angle?

1 answer:

Kobotan [32]2 years ago

8 0

Answer:

Supplementary angle is 180 degrees

Complementary angles are 90 degrees

Explanation:

I’m in honors class. Trust me.

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A system of equations is shown below:

padilas [110]

Answer:

y=3

x=2

Step-by-step explanation:

i have answered it....feel free to ask if u don't get it

8 0

3 years ago

What’s four plus four

strojnjashka [21]

Answer: 8

Step-by-step explanation: four plus four equals eight

4 0

3 years ago

Read 2 more answers

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance

Feliz [49]

Answer:

9.5

Step-by-step explanation:

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.

Step 1

We find the Mean of the numbers

Mean = Sum of terms/ Number of terms

Mean = 9+12+9+14+6/5

= 50/5

= 10

Step 2

We find the sample variance

Formula =

(x - Mean)²/n - 1

n = 5

= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1

= 1+ 4+ 1+ 16+16/5 - 1

= 38/5 - 1

= 38/4

= 9.5

Therefore, Sample variance = 9.5

3 0

2 years ago

Alinara [238K]

Answer:

The answer is 3 hours I think.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers