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IrinaK [193]
3 years ago
13

-6.5+c=-4.12. How do you solve

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Answer: c=2.38

Step-by-step explanation:

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( I'm new at functions ;_; )<br> What is the value of the function y = 2x + 3 ⁢when x=−1 ?
Natali [406]
Answer: y=1
Explanation: all you have to do is plug in “-1” where x is. So you get: y=2(-1) +3.
Simplify and you have -2+3 which is 1

Hope this helped and pls mark as brainliest!

~ Luna
3 0
3 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Find the area of quadrilateral ABCD
LenaWriter [7]

Answer:

it can be solved using the formula hope it will hep you

3 0
3 years ago
Determine the value of x and y in the following systems of equations5x-2y=4 ; -2x+y=2.
V125BC [204]

Answer:(x,y)=(8,18)

Step-by-step explanation:

Given

5x-2y=4-------1

Second Equation

-2x+y=2-----2

Now multiply equation 2 by 2 and it to equation 1

5x-4x+0=8

x=8

substitute it in equation 1

5\times 8-2\times y=4

36=2y

y=18

Therefore

(x,y)=(8,18)

7 0
3 years ago
Russell has been training for the Emerald Valley Race. The first week he trained, he ran 5 days and took the same two routes eac
Ivahew [28]

In maths, Distance is described as the quantity of space between two points, and further calculation can be defined as follows:

Given Expression:

5x + 2 = 30\\\\2(x + 5) = 30\\\\5(x + 2) = 30\\\\2x + 5 = 30

To find:

distance=?

Solution:

5\ days\ \begin{cases} & \text{ if } \text{before school 2 miles}    \\  & \text{ if } \text{after school x miles} \end{cases}

\therefore 5(x+2)=30\\\\

\bold{5(x+2)=30}\\\\\bold{5x+10=30}\\\\\bold{5x=30-10}\\\\\bold{5x=20}\\\\

\bold{x=\frac{20}{4} }\\\\\bold{x=4}

Therefore, the final answer is "4 miles".

Learn more:

brainly.com/question/12186030

8 0
3 years ago
Read 2 more answers
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