Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
And pls mark me brainliesttt :)))
Answer:
Step-by-step explanation:
1 cheeseburger and 20 fries
Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40.
From there use algebraic steps to find out what x is ( the break - even point ).
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40
0.855625x - 4x + 20 = 1.265625x + 6x + 40
-0.41x - 4x + 20 = 6x + 40
-4.41x + 20 = 6x + 40
20 = 10.41x + 40
-20 = 10.41x
-1.92122958694 = x
Rounded to the nearest tenth it's -1.9 = x.
Tell me if I got something wrong :)
I'm not sure if it's 10x or 10 times a number
65.8 + 13.4 = 79 .2. So the answer is c
