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Explanation:</h2><h2>
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Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set
that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
Answer:
35 degrees is the third angle's value.
X-intercept: (-5,0)
Y-intercept: (0,4)
To solve for the X-Intercept, substitute 0 for y and solve for x.
To solve for the Y-Intercept, substitute 0 for x and solve for y.
It’s too blurry to see retake the picture and ask the question again for help