Answer:
-x^6/125-y^3/64
Step-by-step explanation:
that's what it Got
Horizontal distance x(t) = ut cos θ
x(2) = 102 * 2 * cos 67 = 79.7 ft.
Vertical distance y(t) = ut sin θ - 1/2 gt^2
y(3) = 102 * 2 * sin 67 - 1/2 * 9.8 * (3)^2 = 187.78 - 44.1 = 143.7 ft.
The given info is sufficient to warrant the conclusion that both triangles are 45-45-90 triangles.
The measure of angle B is 45 degrees, or pi/4 radians.
The cosine of this angle B is 1/√2, or √(2)/2. This is approx. 0.707.
For each part A through D below, the idea is to find the common factor between the terms, which you'll then use the distributive property to pull out.
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Part A
3x + 18 = 3(x+6)
Note how we pulled out a 3. If we distribute it back in, we end up with 3x+18 again. The other problems are done in a similar fashion
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Part B
2x - 14 = 2(x - 7)
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Part C
6x + 4 = 2(3x + 2)
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Part D
9x - 15 = 3(3x - 5)