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Serjik [45]
3 years ago
7

The distance from point A to one end of the pond is 190 yards, and the distance from A to the other end of the pond is 208 yards

. What is the length of the pond, x, to the nearest yard?

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

x = 150 yards

Step-by-step explanation:

Looking at the diagram, a triangle, ABC is formed.

Let the length of AB be c, so c = 208 yards

Let the length of AC be b, so b = 190 yards

Length of BC = x

To determine x, we will apply the cosine rule since we know two sides and one angle. The cosine rule is expressed as follows

a^2 = b^2 + c^2 - 2bcCosA

Therefore

x^2 = 208^2 + 190^2 - 2×208×190 Cos44

x^2 = 43264+ 36100 - 79040 × 0.7193

x^2 = 79364 - 56853.472

x^2 = 22510.528

x = √22510.528

x = 150 yards

Delvig [45]3 years ago
5 0

Answer:

the answer is 18

hope i helped

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A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
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"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

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