Answer:
9/5 (-8) > = F > = 9/5 (157)
Step-by-step explanation:
A. -40>= 5/9F - 32
-40+32>= 5/9F
9/5(-8) >= F
B. 125 <= 5/9F - 32
125+32 <= 5/9F
9/5(157) <= F
9/5 (-8) >= F >= 9/5 (157)
Answer:
The range is the resulting y-values we get after substituting all the possible x-values.
For the given function : 
<u>See the attached figure.</u>
The zeros of the denominator at x = 0
The domain is: (-∞,0)∪(0,∞)
<u>The range</u> of the function is the domain of the inverse function of f(x)
y = 3/(4x) - 4
y + 4 = 3/(4x)
4x = 3/(y+4)

The zeros of the inverse function:
4(y+4) = 0
y + 4 = 0
y = -4
∴ The range is (-∞,-4)∪(-4,∞)
So, the answer is {y | y > –4} ∪ {y | y < – 4}
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<u>Note</u>: If the given function is : 
It will be first degree polynomial function.
Both of the domain and the range = all real numbers R
recall that the vertical asymptotes come from zeroing out the denominator, thus
x + 3 = 0, x = -3 <--- our only vertical asymptote.