All categories

3 years ago

Solve the two step equations

Mathematics

1 answer:

disa [49]3 years ago

7 0

Hello!

1) -3x - 4 = 23

-3x = 23 + 4

-3x = 27

x = 27 : (-3)

x = -9

2) x/2 - 12 = -4

x - 24 = -8

x = -8 + 24

x = 16

3) 6a + (-1) = 10

6a - 1 = 10

6a = 10 + 1

6a = 11

a = 11 : 6

a = 11/6

4) -(x + 2) = 12

x + 2 = -12

x = -12 - 2

x = -14

5) 7a + 12 = 10

7a = 10 - 12

7a = -2

a = -2 : 7

a = -2/7

6) -4(a + 2) = 12

a + 2 = -3

a = -3 - 2

a = -5

Good luck! :)

You might be interested in

Please help im so confused asap

enyata [817]

Answer:

624

Step-by-step explanation:

the area of the triangles:

12*10 = 120

120/2 = 60

since there are 2 triangles of the same dimensions that make up the surface area 60 + 60 = 120

area of the rectangles:

13*14 = 182

since there are 2 rectangles of the same dimensions 182 + 182 = 364

The last rectangular:

10*14 = 140

add all areas:

120 + 364 + 140 = 624

8 0

2 years ago

Read 2 more answers

A process is turning out end items that have defects of type a, or type b, or both. if the probability of type a defect is 0.1 a

Andreas93 [3]

the probability will end up being
0.28

3 0

3 years ago

Use the diagram below to answer questions 2-3. what is the value of a

Georgia [21]

We have been given a diagram and we need to find the value of arc angle a.

According to one of the circle theorems the angle at the centre of a circle is twice the angle at the circumference subtended by the same arc.

Therefore, arc angle a will be twice of the angle at circumference, that is, 34 degrees.

Therefore, value of angle a is:

$a^{0}=2*34=68^{0}$

8 0

3 years ago

Read 2 more answers

1.) Find the value of the discriminant and the the number of real solutions of

ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

$( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36$

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

D = 0 and therefore we have one real solution.

~ Hope this helps you.

4 0

2 years ago

Read 2 more answers

Graph the line.please help

Levart [38]

Here ya gooooo :))))))

8 0

2 years ago