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Mariulka [41]
3 years ago
9

Please help me out I am not very good at math or graphs.

Mathematics
2 answers:
Stels [109]3 years ago
7 0

Answer: i think its -2

Step-by-step explanation:

Please give me brainliest

Stells [14]3 years ago
3 0

Answer:

Best answer would be 1/2 since the line is going 3 units up and 6 units right

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A 1.5m wire carries a 7 A current when a potential difference of 54 V is applied. What is the resistance of the wire?
borishaifa [10]

Answer:

R = 7.71 ohms

Step-by-step explanation:

By ohm's law: R= V/I

where,  R = resistance of wire, V = potential difference, I = electric current

Given: V = 54 and I = 7 A

Plug in the above values in the ohm's law, we get

R = 54 V/7 A

R = 7.71 ohms

Hope this will helpful.

Thank you.

6 0
3 years ago
Read 2 more answers
How many different primes are in the prime factorization of 65529009
Tems11 [23]

Answer:

6 different primes.

3, 7, 13, 29, 31 , 89.

Step-by-step explanation:

Try dividing by primes starting with 3:

3 ) 65529009

3 )  21843003

7)  7281001

13)  1040143

29)  80011

31 (  2759

             89.   89 is a prime number.

7 0
3 years ago
Please help me with this (i attached photos to cause less confusion) <br><br> Thanks :) 25 Points!!!
navik [9.2K]

Answer:

See below

Step-by-step explanation:

The first two questions are slope = 0

   a horizontal line has zero slope  

            slope = rise/run  = 0 / run = 0

Greatest y value is + 4   from x = 3 to 4

the least y value is -3 fro x = -4 to -3

4 0
2 years ago
Read 2 more answers
Assume that the Poisson distribution applies and that the mean number of aircraft accidents is 9 per month. Find​ P(0), the prob
Ugo [173]

Answer: 0.0001

It is unlikely to have a month with no aircraft​ accidents .

Step-by-step explanation:

Given :  Mean number of aircraft accidents = 9 per month

The Poisson distribution formula :-

\dfrac{e^{-\lambda}\lambda^x}{x!}, where \lambda is the mean of the distribution.

If X = the number of aircraft accidents per month, then the probability that in a​ month, there will be no aircraft accidents will be :-

\dfrac{e^{-9}(9)^0}{0!}=0.000123409804087\approx0.0001

Hence, the probability that in a​ month, there will be no aircraft accidents = 0.0001

Since this is less than 0.5 , therefor it is unlikely to have a month with no aircraft​ accidents .

5 0
3 years ago
And now
shtirl [24]

Answer:

I know another one

Step-by-step explanation:

THERES HYDROIGEN AND HELIUM THEN LITHNIUM BERILIUM BPRON CARBON EVERYWHERE NITROGEN ALL THROUGH THE AIR WITH OXYGEN SO U CAN BREATHE AND FLUORINE FOR UR PRETTY TEETH

4 0
2 years ago
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