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2 years ago

(4,6),(5,7) write in slope intercept form

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

7 0

Answer:

form ?

Step-by-step explanation:

POINTS :D <3

Anestetic [448]2 years ago

4 0

Answer:

y = x + 2

Step-by-step explanation:

Slope intercept form is y = mx + b

With two points, we have two equations.

6 = 4m + b

7 = 5m + b

Subtract the first from the second.

1 = 1m

So m = 1

Plug back in the first.

6 = 4*1 + b

6 = 4 + b

b = 2

So y = x + 2

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Vinil7 [7]

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Answer:

Proportional, y = 3 times x
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Step-by-step explanation:

The graph shows a proportional relationship if it is a straight line that goes through the origin (0, 0). The constant of proportionality can be found by looking for the y-value when x = 1.

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y = 3 times x

2) The graph does not go through the origin. The relationship is Not Proportional.

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2 years ago

Cheryl had 22 charms. She used C charms to make a bracelet then she went to the store and bought 14 more charms. Now she has 25

antiseptic1488 [7]

Answer:

She used 11 charms.

Step-by-step explanation:

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2 years ago

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sertanlavr [38]

Answer:

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Step-by-step explanation:

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3 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

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2 years ago

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katrin [286]

Answer:

The answer is the second one

Step-by-step explanation:

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3 years ago

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