By finding the least common denominator (LCD), and then go from there.
Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
__
Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
Answer:
Step-by-step explanation:
AS we can see the lines are parallel so
2 ( 4x - 3) + 7(x + 3) = 180° ( being so - interior angles)
8x - 6° + 7x + 21° = 180°
15x + 15° = 180°
15x = 180° - 15°
15x = 165°
x = 165° / 15
Therefore x = 11°
Now
2 ( 4x - 3) = 2 ( 4 * 11° - 3°) = 2 ( 44 - 3)° = 2* 41 = 82°
7(x + 3 ) = 7 ( 11° + 3°) = 7 * 14 = 98°
Answer:
Step-by-step explanation:
