| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
The price p based on the equation given is p = 3000 - 0.1x.
<h3>How to express the price?</h3>
The equation given in the question is x = 3000 - 10p. The price(p) will be:
x = 3000 - 10p.
Make p the subject of the formula
x + 10p = 3000
10p = 3000 - x
p = (3000 - x)/10
p = 3000 - 0.1x
The revenue will be price multiplied by quantity. This will be:
= (3000 - 0.1x) × x
= 3000x - 0.1x²
The marginal revenue will be calculated after differentiating. This will be:
= 3000x - 0.1x²
= 3000 - 0.2x
The demand which is the quantity based on the information will be:
3000 - 0.2x = 0
0.2x = 3000
x = 1500
Learn more about demand on:
brainly.com/question/1245771
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Step-by-step explanation:
Kayden:Kayah:Kayla:Michelle
2:3:4:3
2k+3k+4k+3k=36
12k=36
k=36:12
k= 3
Kayden- 2•3=6
Kayah- 3•3=9
Kayla= 4•3=12
Michelle= 3•3=9
Based on the letters representing the the given figure, two different ways that it can be named are CJB and BJC.
<h3>What other ways can the figured be named?</h3><h3 />
The figure has the midpoint of J.
This means that when you are naming the figure, J has to be in the middle of either of the names that you choose.
You can therefore name the shape CJB which would mean that C is the starting point and B is the ending point.
Or you could name it BJC with B being the starting and C being the ending.
Rest of the question:
Shape description is that of a line that has three different points which are C, J, and B.
Find out more on naming figures at brainly.com/question/22749241.
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Answer:
- 4x
Step-by-step explanation:
