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Sever21 [200]
3 years ago
13

I almost got the problem but the problem was the rounding. I believe I rounded right but it is still incorrect. Can someone plea

se help me on the rounding portion of the question? Thank you for your help!!!

Mathematics
1 answer:
ella [17]3 years ago
4 0

Answer: The answer that I got for z was 0.111575, which when you round it to the hundredths place would be 0.11

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110% of 90 is what?????????????????????????????
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110% of 90 is 99, 1.1*90=99
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4 years ago
Abby owns a comic book that originally sold for 12¢ in 1969. In 2014, the comic book had an appraised valued of $3,700. Given th
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Solution

2014 - 1969 = 45

45 x 0.2633 = 11.8485 = 12

Final Answer:

C) 26.33%

6 0
3 years ago
Dawson purchased a pair of shoes on boxing-day that was discounted by 60% from the original price of $150.00. Calculate the amou
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Answer: $90

Step-by-step explanation:

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3 years ago
Read 2 more answers
The ages of registered voters in Smith County are normally distributed with a population standard deviation of 3 years and an un
eimsori [14]

Answer:

The margin of of error for a 95% confidence interval for the population mean is of 1.39 years.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Population standard deviation of 3 years

This means that \sigma = 3

Sample of 18 voters

This means that n = 18

Margin of error:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{3}{\sqrt{18}}

M = 1.39

The margin of of error for a 95% confidence interval for the population mean is of 1.39 years.

3 0
3 years ago
Texas chic for you also
Marat540 [252]
0,1,2,4,4,5,5,24.....median is 4...I believe it is this one
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