Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
The equation is y = (3/7)x - 7.
Step-by-step explanation:
Given that the point slope form of an equation is y = mx + b where m represents the gradient and b is the y-intercept. Then, you have to substitute the following values into the equation :






Answer:
To know what the ratio for the cos of theta, we actually have to see the adjacent and hypotenuse values. cos=adjacent/hypotenuse.
Step-by-step explanation:
Answer:
Answer is 80.36
Step-by-step explanation:
V=πr2h=π·2.12·5.8≈80.35566
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4.5 mph (aka 4 and 1/2 mph)