Attached solution with detailed work.
Answer:
825 g
Step-by-step explanation:
Here's my work:
500g Cl2 l 1mol Cl2 l 2 mol NaCl l 58.5 g NaCl
l 71 g Cl2 l 1 mol Cl2 l 1 mol NaCl
= 823.94 - the rounding can be a little off
The first thing you have to do is convert the 500 g of Cl2 into moles. So you get the mass of Cl which is 35.5, but Cl is diatomic by itself so you multiply 35.5 x 2 and get 71. now on the third column you are comparing the mol ratios of the equation. The equation is 2Na + Cl2 ---> 2NaCl, so you see that there is no coefficient in front of Cl2 so that means there is 1 mol, and then you see that in the product there is a coefficient of 2 in front of NaCl so that means there is 2 moles. Then finally you have to convert the moles backs into grams where you just add the masses of Na and Cl . You multiply across the top and then divide that number by the bottom row.
Answer:
a=10 b=30 c=20
Step-by-step explanation:
10+30=40 30+20=50 20+10=30
Answer:
10
Step-by-step explanation:
Expanding the left side gives
which gives two solutions,
and
. But if
, then
, but this number isn't real, so
is an extraneous solution. Meanwhile if
, you get
, so this solution is correct.
"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
