Since x=8y, subsitute 8y for x in other equation
y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47
subsitute taht for y to find x
x=8y
in (x,y) form
(x,y)
Which is the domain of the function shown in the graph?
A. x ≤ 3
B. -∞ < x < ∞ ( ✔ )
C. x > 0
D. x ≥ 3
Since 6 is positive, it's (x+blank)^2
6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
Three miles a day should be the correct answer
Answer:
x=1
Step-by-step explanation:
For algebra always start by rewriting it.
4+x+2-2x=5
Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.
6-x=5
Now lets get x alone and the quickest way is to subtract 6 to the other side
6-x=5
-6 -6
-x=-1
Now the two negatives cancel out as you would divide both sides by the coefficient -1 to get positive x alone. We can make this easier by just canceling out the negatives.
Your answer is
x=1
