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defon
3 years ago
11

(2/3) to the 3rd power] plus [(3/4) to the zero power]

Mathematics
1 answer:
aniked [119]3 years ago
3 0

<em>Answer:</em>

<em>1-8/27</em>

<em>Step-by-step explanation:</em>

<em />(\frac{2}{3})^3=\frac{8}{27}<em />

<em />(\frac{3}{4})^0=1<em> (anything to the zeroth power is 1)</em>

<em />1+\frac{8}{27}=1\frac{8}{27}<em />

<em>We cannot simplify, so 1-8/27 is our answer.</em>

<em>Hope this helps. Have a nice day.</em>

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At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

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