Find the anti-derivative of \[f \prime \prime(x) = 2e ^{3} 3\sin t\], f(0)=0, f(pi)=0
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Answer:
Here the degree of the polynomial is 11.
Step-by-step explanation:
To find the degree of the multivariate polynomials, we need to add up the powers of all the variables. So the total degree is given by the sum of all the powers of the highest powers terms.
Now in the given polynomial
the term with the highest total powers is and thus the total power is 6+5=11.
And hence the degree of this polynomial is 11.