We have that The height changing rate when the length of the base is 2 cm
From the question we are told
The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is the height changing when the length of the base is 2 cm?
Generally the Pythagoras equation for the triangle is mathematically given
as
With r=3
Therefore
dx/dt=8cm/s
Hence
We have
Therefore
The height changing rate when the length of the base is 2 cm
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x=#of hours worked
33 per hour or 33x (since 33 times every hour)
initial fee is independed of hours so
fee=33x+16
if fee=197 then solve for hours or x
197=33x+16
subtract 16 from both sides
181=33x
divide both sides by 33
5.4848484848=x
he worked 5.48 hours
Answer:equal
Step-by-step explanation:
The probability that a random variable is greater than or equal to z standard deviations from the mean in a standard normal distribution he P(z≤a)+P(z>a)=1, so P(z>a)=1-P(z≤a)=1-.7116=.2884
Answer:
f(32)=3
Step-by-step explanation:
once again plug 32 in for X and you end up with 3
Answer: 5 batches
Step-by-step explanation: 3 1/3 / 2/3 10/3 * 3/2= 5
