Answer:
A
Step-by-step explanation:
I plugged function 2 into desmos and it gave me that it had a bigger rate of change.
The coordinates below represent a triangle that was dilated. J(-3, -12) à J’(-2, -8) K(-6, -15) à K’(-4, -10) L(-9, -12) à L’(-6
1 answer:
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Answer:
23.92°, 78.503°, and 77.577°
Step-by-step explanation:
The coordinates of the vertices of the triangle are;
X(-3, -5), Y(2, 6), Z(6, 3)
The vectors are;
z = =
y = =
x = =
Therefore, we get;
α = arccos(0.91490) ≈ 23.92°
γ = The angle between -y and x
-y =
We get;
Therefore;
γ = arccos(0.199309) ≈ 78.503°
γ ≈ 78.503°
By angle sum property, β = 180° - (α + β)
β ≈ 180° - (23.92° + 78.503°) = 77.577°
β ≈ 77.577°
The interior angles are;
23.92°, 78.503°, and 77.577°
I’m not totally sure about the less and greater signs because I’m not sure you can graph using those signs but either way their are your line equations
