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Ahat [919]
3 years ago
11

Which sentence is true about an equiangular triangle

Mathematics
2 answers:
lions [1.4K]3 years ago
7 0

Answer:

E

Step-by-step explanation:

its equal triangle hope this helped good luck

Natasha_Volkova [10]3 years ago
3 0

Answer:

E

Step-by-step explanation:

it has equi which means equal then it has angle. Equal angle triangle

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7 0
4 years ago
During a store's closing sale, everything is 65% off. Vikram goes into the store to buy a shirt and a pair of pants, and spends
saw5 [17]

Answer:

without the sales, he would have spent $44.57

Step-by-step explanation:

Let the amount he would have spent without the sales be x. Now, if there is a 65% discount, what this means is that he is exactly paying for 100 - 65% = 35%

Now, it is this 35% of X that is equal to the amount he paid

Thus, mathematically, we have the following;

35/100 * x = 15.60

35x = 15.6 * 100

35x = 1560

x = 1560/35

x = $44.57

This means that without the sales discount, he would have paid $44.57

5 0
3 years ago
12+7+5x in the expression above there are three terms- )
mina [271]
( 12 + 7) 5x = 95 so that's your answer
8 0
3 years ago
Read 2 more answers
On a map, 90 miles is represented by 3 inches. A measure of inch on the map would represent miles.
yuradex [85]

Complete Question

On a map, 90 miles is represented by 3 inches. A measure of 1/2 inch on the map would represent miles.

Answer:

15 miles

Step-by-step explanation:

From the above question,

3 inches = 90 miles

1/2 inch = x miles

Cross Multiply

3 inches × x miles = 90 miles × 1/2 inch

x miles = 90 miles × 1/2 inch/3 inches

x miles = 15 miles

Therefore, a measure of 1/2 inch on the map would represent 15 miles

4 0
3 years ago
$20000 is invested in an account that earned 6% p.A. Compounding yearly for 3 years. The interest rate then went up to 8% p.A. F
GuDViN [60]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the first 3 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases}

\bf A=20000\left(1+\frac{0.06}{1}\right)^{1\cdot 3}\implies A=20000(1.06)^3\implies \boxed{A=2382.032} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the next 4 years}}

\bf A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2382.032\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}

\bf A=2382.032\left(1+\frac{0.08}{1}\right)^{1\cdot 4}\implies A=2382.032(1.08)^4\implies \boxed{A\approx 3240.73} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{amount for this period}}{2382.032+3240.73}\implies 5622.762

4 0
4 years ago
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