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8_murik_8 [283]
3 years ago
7

Find the area of the square ABCD.

Mathematics
2 answers:
zmey [24]3 years ago
4 0

Answer:

Step-by-step explanation:

area of square is basically one side times itself

14 times 14 =196m^2

True [87]3 years ago
3 0

Answer:

Area of the given square =

196m {}^{2}

Step-by-step explanation:

area of square = side × side

  • area = 14 × 14
  • area = 196

i hope it helped...

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D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

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1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

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* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

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23 is 12% of what number
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\frac { 12 }{ 100 } \cdot x=23\\ \\ \Rightarrow \quad \frac { 3 }{ 25 } \cdot x=23\\ \\ \Rightarrow \quad \frac { 25 }{ 3 } \cdot \frac { 3 }{ 25 } \cdot x=23\cdot \frac { 25 }{ 3 } \\ \\ \Rightarrow \quad x=\frac { \left( 20+3 \right) \left( 25 \right)  }{ 3 } \\ \\ \Rightarrow \quad x=\frac { 500+75 }{ 3 } \\ \\ \Rightarrow \quad x=\frac { 575 }{ 3 }
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