All categories

3 years ago

Make the following conversion. 4mm = _____ cm 0.04 0.4 40 400

Mathematics

2 answers:

wel3 years ago

7 0

Answer:

0.4 cm

Step-by-step explanation:

10 mm = 1 cm thus 4mm / 10 = 0.4 cm

eimsori [14]3 years ago

6 0

Answer:

10 mm = 1 cm

4 mm = 4/10 cm

=0.4 cm

hope it helps

You might be interested in

What is the volume of a solid if the height is 4in and the base is 18 inches squared

zubka84 [21]

4in x 18in^2= 72 inches cubed

4 0

2 years ago

Find the volume of the triangular prism

Marianna [84]

63 m3

9×2=18

18×7=126

126÷2=63

7 0

2 years ago

Multiply: 2.7 × (–3) × (–1.2). A. –9.72 B. –10.8 C. 10.8 D. 9.72

Vikentia [17]

Answer: $\text{ D) } 9.72$

Step-by-step explanation:

Here the give expression is,

$2.7 \times(-3)\times (-1.2)$

We can write,

$2.7 \times(-3)\times (-1.2) = 2.7 \times 3.6$ ( because $-a\times -b = ab$ )

$2.7 \times(-3)\times (-1.2) = 9.72$

⇒ Option D is correct.

6 0

2 years ago

Read 2 more answers

I really need help with this one

Novay_Z [31]

Answer:

Step-by-step explanation:

Since B is the midpoint of AC, that means AB = BC. That means 3x+4 = 5x-6. We can now set up an equation to solve for x:

3x+4 = 5x-6

3x+10 = 5x

10 = 2x

x = 5

Now that we know what x is, we can just plug x into the expression of AB and multiply it by 2:

(3*(5)+4)*2

=(15+4)*2

=19*2

=28

(side note: we could have plugged x into the expression of BC as well, but in this case plugging it into AB tends to be easier to solve)

Therefore, the length of AC is 28.

3 0

3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago