Help me please. Very much appreciated
2 answers:
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Answer:
h = 2.82 cm
Step-by-step explanation:
Answer:
The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.
Step-by-step explanation:
Test if the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135
This means that the null hypothesis is:
And the alternate hypothesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.135 is tested at the null hypothesis:
This means that
Of the 710 infants,121 experienced a loss of appetite.
This means that
Value of the test-statistic:
Pvalue of the test and decision:
The pvalue of the test is the pobability that the population proportion differs from the tested proportion by at least 0.1704 - 0.135 = 0.0354, which is P(|z| > 2.76). This probability is 2 multiplied by the pvalue of z = -2.76.
Looking at the z-table, z = -2.76 has a pvalue of 0.0029
2*0.0029 = 0.0058
The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.