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Arisa [49]
3 years ago
8

Help me please. Very much appreciated​

Mathematics
2 answers:
worty [1.4K]3 years ago
3 0

Divide the figure into 3 shapes: 2 rectangles and 1 square

Area of rectangle 1: L * W

L = 5, W = 2

2 * 5 = 10 m^2

Area of rectangle 2: L * W

L = 6 + 2 , W = 3

8 * 3 = 24 m^2

Area of square: s^2

2^2 = 4 m^2

Add all them together

10 + 24 + 4 = 38 m^2

SashulF [63]3 years ago
3 0

Step-by-step explanation:

Area of the top Horizontal Rectangle =

Length x Width

=

(5 + 3 + 2) \times 2 \\  = 10 \times 2 \\  = 20 {m}^{2}

Area of the bottom vertical rectangle =

Length x Width

=

6 \times 3 \\  = 18 {m}^{2}

Total Area = Sum of Area of 2 Rectangles

=

20 + 18 \\  = 38 {m}^{2}

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Answer: None

Step-by-step explanation:

y=0 and y=-5 don't have any solutions. When you ask if a pair of equations have a solution, that means there is an intersection of the equations. The 2 equations will meet somewhere, and that is the solution. To find the solution, you set the equations equal to each other.

0≠-5

It is obvious that 0 and -5 are not equal to each other. Therefore, there is no solution. Also, y=0 and y=-5 are horizontal lines that are parallel to each other. They will never meet, which means there will be no intersection. No intersection means no solutions.

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