Answer:
A, C, D
Step-by-step explanation:
A. $5.60 per class
$196 divided by 35
B. $6.50 per class
$260 divided by 40
C. $5.00 per class
$250 divided by 50
D. $5.50 per class
$55 divided by 10
E. $7.60 per class
$342 divided by 45
Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±
* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!
Answer:
A^-1:B^-1
Step-by-step explanation:
im not 100% sure but i think this is the right answer :)
The half-life of the radioactive substance is 67.95 hours.