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Arte-miy333 [17]
2 years ago
6

Please help me I will give you the brain thing and extra points. (image below) 18/30

Mathematics
2 answers:
uranmaximum [27]2 years ago
6 0

Answer:

B

Step-by-step explanation:

sjsjsjsjsjjsjsjsjdjdjjdjdjs

GrogVix [38]2 years ago
5 0

Answer:B

Step-by-step explanation:

Hi

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What is the slope of this line? -2x + 3y =-6
valkas [14]

Answer:

Slope: 2/3

Step-by-step explanation:

You have to first write the equation into slope-intercept form...

y = mx + b

So...

-2x + 3y = -6

becomes...

3y = 2x - 6

y = 2/3x - 2

Which means...

2/3 is the slope

Hope this help :)

Let me know if there are any mistakes!!

4 0
2 years ago
What is the sum of the arithmetic series
docker41 [41]

Answer:

S_ {12} = 192

Step-by-step explanation:

The nth term of the given arithmetic sequence is

U_n = 3 + 2n

The first term of this series is:

U_1 = 3 + 2(1) = 5

The last term of this series is when

n = 12

U_ {12}= 3 + 2(12)

U_ {12}= 3 + 24 = 27

The sum of the first n terms of an arithmetic series when the first an last term is known is given by:

S_n =  \frac{n}{2}(a + l)

Where a=5 is the first term and l=27 is the last term.

S_ {12} =  \frac{12}{2}(5 + 27)

S_ {12} =6(32) =19 2

6 0
3 years ago
The point (5,6) is the solution to which of the following systems of equations
VikaD [51]

Answer:

i dont know

Step-by-step explanation:

e

3 0
2 years ago
2. What is 9 squared. <br> a. 3<br> b. 81<br> C. 18<br> O d. 11
vitfil [10]

Answer:

81

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
If f(x) = (x + 9 and g(x) = --6, which describes the range of (f + g)(x)?
S_A_V [24]

Given:

Consider the below figure attached with this question.

To find:

The value of (f+g)(x).

Solution:

The given functions are:

f(x)=|x|+9

g(x)=-6

Now,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=|x|+9+(-6)

(f+g)(x)=|x|+9-6

(f+g)(x)=|x|+3

We know that,

|x|\geq 0

Adding 3 on both sides, we get

|x|+3\geq 0+3

(f+g)(x)\geq 3

So, (f+g)(x)\geq 3 for all values of x.

Hence, the correct option is A.

6 0
3 years ago
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